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Over the summer, the High Court in London ruled that the Conservative government acted unlawfully in trying to prevent local councils in the UK from divesting from firms involved in Israel’s military occupation, dealing a blow to Israel’s representatives seeking to criminalize the BDS movement.

Meanwhile, in the face of Israel’s overt attempts to silence him and crush the popularity of BDS, Omar Barghouti , the co-founder of the BDS movement, urged people around the world to increase boycott campaigns as the best way to show support for him and for the Palestinian people.

Barghouti the Gandhi Peace Award in April for his work as a human rights defender. He had been subjected by Israel to a travel ban and open threats by that state’s top ministers last year.

In March, Barghouti praised a Mens PW Minor Natural Strap Clay 5OJKpZ3
published by the United Nations which concluded that Israel is guilty of the crime of apartheid, drawing praise from Palestinians and ire from Israel and its allies.

Barghouti said the UN report was a sign for Palestinians that “our South Africa moment is nearing,” adding that the report was “a stark indicator that Israel’s apartheid is destined to end, as South Africa’s did.”

He remarked that the report “may well be the very first beam of light that ushers the dawn of sanctions against Israel’s regime of occupation, settler-colonialism and apartheid.”

Here are some of the other victories of the BDS movement in 2017, as reported by The Electronic Intifada.

In February, professional US football players pulled out of a propaganda tour to Israel, with Seattle Seahawks player Michael Bennett announcing he would “not be used” by Israel’s government to whitewash its violations of Palestinian rights.

“I want to be a ‘voice for the voiceless,’” Bennett added, “and I cannot do that by going on this kind of trip to Israel.”

In August, nine international artists pulled out of the Pop-Kultur festival in Germany because it accepted funding from the Israeli embassy. Palestinian campaigners said the “eloquent statements from the artists stand in stark contrast to the festival’s crude attempts to falsely portray the Palestinian boycott call as directed at individual Israeli artists, shrewdly omitting the fact that the protests were clearly aimed at the Israeli government involvement.”

German media also joined in the smears, giving a platform to false accusations the boycott was an “anti-Semitic” move by “participants from various Arab nations.” But the pro-Israel spin was ably confronted by German Jewish and Israeli activists, who fully backed the boycott.

Over the summer, a group of filmmakers, artists and presenters canceled their scheduled appearances at TLVFest, Israel’s premier LGBTQ film festival in Tel Aviv, following appeals by queer Palestinian activists and boycott supporters to withdraw.

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From Lizhong Zheng's Research Page

## Contents

Construct a straight line through the given point $A$ that makes an angle of ${60}^{\circ }$ with the given line.

Goal: 3L, 4E

This is actually one of the cool and simple solutions. To see how it works, we need one auxiliary line as follows:

From the constructions, a few things are obvious

$\angle BAD={60}^{\circ }$ ,

$\angle ABC=\angle ACB$ , and

\left \{ \begin{array}{@{}l} \langle B_{1}u_{n},u-u_{n}\rangle +\phi(u)-\phi(u_{n})+\frac{1}{r_{n}}\langle u-u_{n},u_{n}-x_{n}\rangle \geq0, \quad\forall u\in C;\\ {\langle B_{2}(v_{n}),v-v_{n}\rangle +\varphi(v)-\varphi(v_{n})+\frac {1}{r_{n}}\langle v-v_{n},v_{n}-y_{n}\rangle \geq0, \quad\forall v\in Q};\\ {x_{n+1}= \alpha_{n} u_{n}+ (1- \alpha_{n})T(u_{n}- \rho_{n} A^{*}(Au_{n}-Bv_{n}))};\\ y_{n+1}= \alpha_{n}v_{n}+ ( 1- \alpha_{n})S(v_{n}+ \rho_{n} B^{*}(Au_{n}-Bv_{n})), \quad\forall n\geq1; \end{array} \right .

0<\alpha\leq\alpha_{n}\leq\beta<1 ( \alpha, \beta\in (0,1) );

\liminf_{n\rightarrow\infty}r_{n}>0 \lim_{n\rightarrow\infty }|r_{n+1}-r_{n}|=0 .

\{(x_{n}, y_{n})\} ( ).

, , -, \{ (x_{n},y_{n})\} ( ).

In Theorem taking B=I and H_{2}=H_{3} , from Theorem we can obtain the following convergence theorem for split mixed variational inequality problem SMVIP(\phi,\varphi) .

\left \{ \begin{array}{@{}l} \langle B_{1}u_{n},u-u_{n}\rangle +\phi(u)-\phi(u_{n})+\frac{1}{r_{n}}\langle u-u_{n},u_{n}-x_{n}\rangle \geq0, \quad\forall u\in C;\\ {\langle B_{2}(v_{n}),v-v_{n}\rangle +\varphi(v)-\varphi(v_{n})+\frac {1}{r_{n}}\langle v-v_{n},v_{n}-y_{n}\rangle \geq0,\quad \forall v\in Q};\\ {x_{n+1}= \alpha_{n} u_{n}+ (1- \alpha_{n})T(u_{n}- \rho_{n} A^{*}(Au_{n}-v_{n}))};\\ y_{n+1}= \alpha_{n}v_{n}+ ( 1- \alpha_{n})S(v_{n}+ \rho_{n} (Au_{n}-v_{n})), \quad\forall n\geq1; \end{array} \right .

0<\alpha\leq\alpha_{n}\leq\beta<1 ( \alpha, \beta\in (0,1) );

\liminf_{n\rightarrow\infty}r_{n}>0 \lim_{n\rightarrow\infty }|r_{n+1}-r_{n}|=0 .

\{(x_{n}, y_{n})\} ( ).

, , -, \{ (x_{n},y_{n})\} ( ).

It is easy to see that the split equality mixed equilibrium problem ( ) reduces to the split equality convex minimization problem ( ) as F=0 and G=0 . Therefore, Theorem can be used to solve split equality convex minimization problem ( ), and the following result can be directly deduced from Theorem .

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